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4m^2-68m+168=0
a = 4; b = -68; c = +168;
Δ = b2-4ac
Δ = -682-4·4·168
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-44}{2*4}=\frac{24}{8} =3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+44}{2*4}=\frac{112}{8} =14 $
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